Ken Davey said:Bob (this one) said:Ken Davey said:Bob (this one) wrote:
>Alan S wrote:
>
>>"Ken Davey" <[email hidden]> wrote in message
>>news:[email hidden]...
>>
>The shiny side will reflect *light* more obviously because the dull
>side is not as smooth and will do more diffusion. Heat will be
>absorbed equally by either surface.
Sorry - this is not correct.
The degree of reflection (or absorption) of light is almost
identical to the degree of reflection of heat.
I didn't say it would reflect more light, I said the reflection would
be more obvious. On the shiny side, it looks like a mirror and
reflects a more familiar image. The dull side is less "polished" and
therefore
doesn't reflect an image as crisply. But the same amount of light is
hitting and bouncing off. It's just more scattered from the dull side
and is a more spread-out reflectance. Same total reflectivity from
either side. One side is "prettier."
Again I have to say - not true.
Sigh.
Time for a 'basic' lesson in physics.
<sigh> Ok.
Quoted message said:Firstly let me say there is *no* perfect reflector.
Now *all* surfaces reflect heat/light.
You need to take a walk through the Hirschhorn museum to see the "Black
Hole" that's a hemisphere with such a low albedo that you can't focus
your eyes on it. In normal, bright museum light, it's the blackest thing
I've ever seen. Or, rather, not seen.
Quoted message said:A perfect surface would reflect 100% of the light/heat (same thing - really)
Now, as I said, there is no such thing as a perfect reflector.
All surfaces absorb some of the energy that strikes them.
And - the rougher the surface the more the energy that gets absorbed and the
less that gets reflected.
This is an immutable law of physics.
With a good definition of "rough" that includes certain characteristics.
A wavy mirror and a flat mirror will have virtually no difference in
their energy performance. It's not until the irregularities begin to
force reflection to another part of the surface that any increase in
energy absorption occurs.
Quoted message said:To explain let's compare the shiny and dull side of a piece of aluminum
foil.
The shiny side has a surface that has fewer imperfections than the dull
side.
By imperfections (in the context of this discussion) the dull side has hills
and valleys and voids that, in effect, 'trap' rays of light/energy.
That's guesswork. There are certainly surface irregularities, but the
necessary physical condition for your thesis to obtain is for the
valleys and hills to be jagged and capable of trapping light for many
bounces before exiting. Being non-specular, reflections from the dull
side merely demonstrate that there are many angles of
incidence/reflectance at work, but they don't necessarily imply an
appreciable difference in energy absorption.
Quoted message said:By trap I mean that the light bounces around in these 'imperfections' and at
each 'bounce' some energy is absorbed into the surface.
The rougher the surface the more the 'bounce' and more energy is absorbed
reather than reflected.
Dealing with light, the energy is trivial. Dealing with heat scales up
the quantities a good bit. The assumption of "imperfections" capable of
trapping heat or light is guesswork.
Quoted message said:You are correct that it is a guess as to how much more energy is
absorbed/reflected shiny versus dull but it is measurable and is observable
when the foil is utilized in cooking (Finally on topic!).
This is in the realm of laboratory micro-measurements, not kitchens. The
energy delta between the two sides will be meaninglessly small in
practical application. I'd be interested to see some hard numbers about
this. My own experience with foil in restaurant use doesn't bear it out.
Quoted message said:I have tried to find a definitive study on this subject but had to give up
after wading through thousands of web pages.
This is not meant to be a 'lecture'.
Basic physics is poorly understood by most people but in this case it can be
used to prove that there is a significant difference between the shiny and
the dull side of a piece of foil.
Here;'s a funny "Ask a scientist" site I just found:
<http://www.newton.dep.anl.gov/askasci/gen01/gen01407.htm>
Scientists disagreeing with each other. Wonderful.
Quoted message said:And we are not discussing conduction or convection - that is a totally
unrelated topic..
As I'm seeing it, the conversation is about heat transfer/reflectivity
in aluminum foil.
Pastorio
Quoted message said:Quoted message said:Quoted message said:Radiant heat is simply a different wave length.
But conducted and convected heat also play their roles here.
Quoted message said:The difference in heat transferrence between the shiny side versus
the dull side is not trivial.
This is a guess.
Quoted message said:Quoted message said:It would be interesting to get someone who is in school and studying
physics (they do still teach that?) to set up an experiment to
measure and quantify the difference.