Cycling Equipment · Public discussion

Power = Speed Cubed; the Propeller Rule

Started by Bretcahill · · Last activity · 10 posts · 1,107 views

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Cycling Equipment
Published
16 September 2003
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19 September 2003
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Bretcahill
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  1. According to the propeller rule, a boat needs eight times times more power to double speed, 27 times
    more power to triple speed.

    Does this hold for air?

    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    Bret Cahill

  2. BretCahill said:

    According to the propeller rule, a boat needs eight times times more power to double speed, 27
    times more power to triple speed.

    Does this hold for air?

    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    analyticcycling.comForcesPower Page.html

  3. Quoted post said:

    Originally posted by Bretcahill
    According to the propeller rule, a boat needs eight times times more power to double speed, 27 times
    more power to triple speed.

    Does this hold for air?

    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    Bret Cahill


    No.

    Fluidic resistances such as water and wind on a bike or water-craft increase in proportion to the square of velocity.

    Rolling resistances on a bike increase linearly proportional to velocity.
    On a bike, the wind resistance is typically about 80% of the total resistance at about 18 mph. If you extrapolated this relationship to 24 mph, 84.3% of total bike resistance is wind resistance.
    At 30 mph you would use 1.51 times as much power as at 24 mph.
    at 34.9 mph you would TT with the example bike at double the power of a 24 mph speed.

    Watercraft face all their moving resistance in water + wind resistance-resistances that increase in proportion to the velocity square virtually nothing incerasing linearly with velocity.
    Energy is lost out from the propeller propulsion system pushing the water back.
    Hydroplane racers often say they loose half the drivetrain energy in the propeller driven spray. Its not apparent to me why they loose that much power from the propeller, but that statement exactly coincides with the 8x propeller rule you cited when you multiply by two the change in power needed to overcome the watercrafts fluidic resistance.

    Robert’s cited link is appropriate for bikes.

  4. I think the power required is proportional to the square of the (net) velocity
    156.25% from 24 to 30

    nick

    "BretCahill" <[email hidden]> wrote in message
    "]news:[email hidden]... According to the propeller rule, a boat needs
    eight times times more power to double speed, 27 times more power to triple speed.

    Does this hold for air?

    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    Bret Cahill

  5. [email hidden] (BretCahill) wrote in message
    news:<[email hidden]>...

    Quoted message said:

    According to the propeller rule, a boat needs eight times times more power to double speed, 27
    times more power to triple speed.

    Does this hold for air?

    The short answer is yes, because the force required to overcome aerodynamic drag increases as the
    square of the speed, and power is speed times force.

    Quoted message said:


    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    Bret Cahill

  6. Nicholas & Domino said:

    I think the power required is proportional to the square of the (net) velocity
    156.25% from 24 to 30

    nick

    "BretCahill" <[email hidden]> wrote in message
    "]news:[email hidden]... According to the propeller rule, a boat needs
    eight times times more power to double speed, 27 times more power to triple speed.

    Does this hold for air?

    If so, it takes almost twice as much power to time trial at 30 mph as 24 mph.

    Bret Cahill


    The force required goes roughly with the square of the speed thus the power goes with the cube of
    the speed.

  7. "dr. dave" <[email hidden]> wrote in message
    news:<[email hidden]>... <snip>

    Quoted message said:

    The force required goes roughly with the square of the speed thus the power goes with the cube of
    the speed.

    In other words, streamlining pays big dividends. Take a look at the bikes running at the World Human
    Powered Speed Challenge: wisil.recumbents.comresultsmonday.htm and check
    out their speeds: wisil.recumbents.comresults.htm

    Jeff

  8. Jeff Wills said:
    Quoted message said:

    The force required goes roughly with the square of the speed thus the power goes with the cube
    of the speed.

    In other words, streamlining pays big dividends. Take a look at the bikes running at the World
    Human Powered Speed Challenge: wisil.recumbents.comresultsmonday.htm
    and check out their speeds: wisil.recumbents.comresults.htm

    Actually just the opposite. The higher the exponent (3), the less difference streamlining makes. If
    you halve the drag coefficient you get only the cube root of two increase in speed (1.26). With
    linear power it would double.
    --
    Ron Hardin [email hidden]

    On the internet, nobody knows you're a jerk.

  9. "Ron Hardin" <[email hidden]> wrote in message "]news:[email hidden]...

    Quoted message said:
    Jeff Wills said:
    Quoted message said:

    The force required goes roughly with the square of the speed thus the power goes with the cube
    of the speed.

    In other words, streamlining pays big dividends. Take a look at the bikes running at the World
    Human Powered Speed Challenge: wisil.recumbents.comresultsmonday.htm
    and check out their speeds: wisil.recumbents.comresults.htm

    Actually just the opposite. The higher the exponent (3), the less


    difference

    Quoted message said:

    streamlining makes. If you halve the drag coefficient you get only the


    cube root

    Quoted message said:

    of two increase in speed (1.26). With linear power it would double.

    I guess you could look at it that way - but since we know a priori that drag in a fluid medium
    increases as a square of the velocity (such that power increases as a cubic function), the statement
    "streamlining pays big dividends" implies that air (or water) resistance is the dominant force to be
    overcome. Systems in which the power requirement increases as a linear function of velocity are
    obviously those in which velocity is low (e.g., climbing a steep hill).

    Andy Coggan

  10. Andy Coggan said:
    Quoted message said:

    Actually just the opposite. The higher the exponent (3), the less


    difference

    Quoted message said:

    streamlining makes. If you halve the drag coefficient you get only the


    cube root

    Quoted message said:

    of two increase in speed (1.26). With linear power it would double.

    I guess you could look at it that way - but since we know a priori that drag in a fluid medium
    increases as a square of the velocity (such that power increases as a cubic function), the
    statement "streamlining pays big dividends" implies that air (or water) resistance is the dominant
    force to be overcome. Systems in which the power requirement increases as a linear function of
    velocity are obviously those in which velocity is low (e.g., climbing a steep hill).

    In some systems, a constant speed is wanted, eg. clock escapements, and I guess door closers (I
    don't know how these work), regardless of force. I think these have a very high exponent in the drag
    law, the clock in effect, and the door closer I don't know about.
    --
    Ron Hardin [email hidden]

    On the internet, nobody knows you're a jerk.

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