The Moloney's said:
I am building a single speed disc wheel for my 29er. I am going to lace a Paul SS WORD disc hub
into a 36 hole Mavic T520.
I weigh 215 fully loaded and ride mostly rooty, rocky single track.
Which would be a better lacing for me 3 or 4 cross?
You can probably use either successfully, but 3x is certainly more common. However, I don't know the
dimensions for your components. Regarding hub and rim spoke angles for some other rather common hub
and rim dimensions, the following provides a feel for what will result:
For 36 hole, 3 cross, 45 mm hub dia, 600 mm rim:
Quoted message said:Quoted message said:[hubSpAng, rimSpAng] = spokeangle(36/2, 3, 45, 600)
hubSpAng =
63. 8606
rimSpAng =
64. 8606
For 36 hole, 4 cross, 45 mm hub dia, 600 mm rim:
Quoted message said:Quoted message said:[hubSpAng, rimSpAng] = spokeangle(36/2, 4, 45, 600)
hubSpAng =
65. 2798
rimSpAng =
66. 2798
Obviously 4 cross is closer to tangential. As a side note, JB's book _The Bicycle Wheel_ lists a
"spoke angle" in the spoke length formula given at the rear of the text: it is *not* the relevant
spoke angle, although it works perfectly for the purpose of computing spoke length. I have given you
the relevant result here.
For those who give a [censored], the simple MATLAB code I wrote and used is as follows:
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
function [hubSpAng, rimSpAng] = spokeangle(No, X, hubRad, rimRad)
%SPOKEANGLE Compute angle of spoke from radial.
%
%
% Syntax: [hubSpAng, rimSpAng] = spokeangle(No, X, hubRad, rimRad)
%
% No := Number of spokes on *one* side of hub.
% X := Number of spoke crosses. hubRad := Radius of hub's spoke hole diameter. rimRad :=
% Radius of rim's spoke hole diameter.
%hubSpAng := Spoke angle from perpendicular to hub circumference (degrees). %rimSpAng := Spoke angle
from perpendicular to rim circumference (degrees).
%
[No, X] = meshgrid(No,X);
hole2holeAngle = 2*pi./No; holeCrossAngle = hole2holeAngle.*X;
a = (cos(holeCrossAngle) - hubRad./rimRad)./sin(holeCrossAngle); hubSpAng = (180/pi)*atan2(1,a);
rimSpAng = (180/pi)*asin(sin(holeCrossAngle)./sqrt(1 + (rimRad./hubRad).^2 -
2*(rimRad./hubRad).*cos(holeCrossAngle)));