Road Cycling · Public discussion

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Started by MagillaGorilla · · Last activity · 7 posts · 470 views

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Original section
Road Cycling
Published
13 December 2007
Last activity
14 December 2007
Original author
MagillaGorilla
Posts
7
Discussion status
Public discussion
Total views
470
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  1. http://www.velonews.com/news/fea/13787.0.html

    The real question is why would the UCI give a racing license to a
    Siberian Husky?

    Magilla

  2. MagillaGorilla said:

    http://www.velonews.com/news/fea/13787.0.html

    The real question is why would the UCI give a racing license to a
    Siberian Husky?

    Magilla

    dumbass,

    i printed out that interview, ground it up and snorted it.

    we are one stage away from seeing vince mcmahon driving a team car.

  3. Quoted post said:

    On Dec 13, 5:14 am, "[email hidden]" <[email hidden]>

    Quoted message said:

    i printed out that interview, ground it up and snorted it.

    what kind of buzz did it give you?

    it made me bombastic and paranoid - like i was sitting in the viper
    room with mr. diesel jeans himself.

  4. In article
    <[email hidden]
    egroups.com>,

    Quoted post said:
    MagillaGorilla said:

    http://www.velonews.com/news/fea/13787.0.html

    The real question is why would the UCI give a racing license to a
    Siberian Husky?

    Magilla

    dumbass,

    i printed out that interview, ground it up and snorted it.

    we are one stage away from seeing vince mcmahon driving a team car.

    Interesting times.
    He makes Chris Horner and USADA look good.

    --
    Michael Press

  5. Quoted message said:

    it made me bombastic and paranoid

    So whats new ?

  6. Donald Munro said:
    Quoted message said:

    it made me bombastic and paranoid

    So whats new ?

    E/h

    --
    Bill Asher

  7. Quoted message said:
    Quoted message said:
    Quoted message said:

    it made me bombastic and paranoid

    Donald Munro said:
    Quoted message said:

    So whats new ?

    William Asher said:

    E/h

    E = h(Gd)^1/2

    It must be true; a trainee accountant who groks
    string theory told me.

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