Here's a good estimate based on my standing start performance. I can do a standing 100m in a 48x14 in around 9.5 seconds. Here's the quick way to calculate torque based on my numbers using the laws of physics:
Newton's 2nd law states Force = mass * acceleration or F=ma. (* is multiplication)
My average acceleration for the 100m start can be obtained by using the equation x=1/2a*t^2. (x is distance in meters and t^2 is time in seconds "squared".)
x=100m, t=9.5s, so a=2.21m/s/s
My mass with bicycle is around 90kg. Using these numbers I can solve for the force. This will be force at the tire/track contact point.
F=90kg*2.21m/s/s
F=200N
To convert force to torque, we need to know the radius of the tire. It's around 340mm (0.340m) if I recall correctly. Torque(T) is T=F*r where r is the tire radius. That means my axle torque is:
T=200N * 0.340m = 68Nm (or around 50ftlb.)
This is NOT at the crank though. At the crank there is more torque by a factor of the gear ratio. The ratio is 48/14=3.43.
So, at the crank I'm making on average over a 100m standing start:
68Nm * 3.43 = 233Nm torque.
Humans do not produce constant torque around the pedal stroke. Plotted out it would look much like a series of humps with flat spots of near-zero torque when the cranks are near the top and bottom of the stroke. This implies that the 233Nm average is a consequence of peaks rather larger than that, averaged together with flat spots of near-zero torque. Using a common RMS(root mean square) estimation, I'm making peak torque of 233Nm * 1.41 = 329Nm (or 244lbft) of torque at the cranks. If this sounds crazy, think about it this way... the pedal force would me a max of only 431lbs. Just standing on the crank I'm getting 180lbs (my bodyweight) into it. That means that the combination of my 400lb-squat-capable front leg and my rear leg pulling upwards while accelerating is making an additional 251lbs of force.
The peak axle torque by the same argument would be around 50*1.41=70.5ftlbs.
This being averaged over 100m, I'm not sure how much the best stroke among those strokes would have attained. I'd think it'd be fairly constant once underway, but perhaps a bit higher at the first few strokes.
Last comment...promise. This all is a slight underestimate also since it neglects wind resistance (my time in the very first calculation would have been faster without wind). I figure it's within 10% though. A standing 50m time would be better, but I don't know mine. Hope this helps.